Latihan
Latihan tambahan
6 soalan untuk mengukuhkan unit Kenal Carta Pai. Jika salah, baca petunjuk dan cuba lagi.
Berapakah murid yang suka rambutan?
读一个扇区 = baca satu sektor
在图例找到红毛丹,它是蓝色。圆里蓝色扇区写着 10,所以喜欢红毛丹的有 10 人。14 是橙色(榴莲),8 是绿色(山竹),都是颜色看错了。
例子:要找香蕉,就找红色扇区,读到 6。
注意:先看颜色,再读数字。
reading one sector = baca satu sektor
In the key, rambutan is blue. The blue sector in the circle shows 10, so 10 pupils like rambutan. 14 is the orange sector (durian) and 8 is the green one (mangosteen); both come from matching the wrong colour.
Example: to find banana, look at the red sector, which reads 6.
Watch out: match the colour first, then read the number.
Buah manakah yang paling kurang disukai?
最少人喜欢 = paling kurang disukai
四个数字是榴莲 14、红毛丹 10、山竹 8、香蕉 6。最小的是 6,香蕉的扇区也最小,所以最少人喜欢香蕉。榴莲 14 是最多的,刚好相反;山竹 8 是第二少。
例子:如果香蕉多了 4 人变成 10,最少的就变成山竹。
注意:paling kurang 和 paling sedikit 意思一样,都是找最小的数。
liked by the fewest = paling kurang disukai
The values are durian 14, rambutan 10, mangosteen 8 and banana 6. The smallest is 6, and the banana sector is also the smallest, so banana is liked by the fewest. Durian with 14 is the opposite, the most, and mangosteen with 8 is second smallest.
Example: if banana gained 4 more pupils to make 10, mangosteen would become the least liked.
Watch out: paling kurang means the same as paling sedikit; both ask for the smallest number.
Berapakah jumlah murid dalam carta pai ini?
全部人数 = jumlah murid
把四个扇区加起来:14 + 10 = 24,24 + 8 = 32,32 + 6 = 38,一共 38 人。选 32 是漏了香蕉的 6;选 28 是漏了红毛丹的 10。
例子:扇区 10、10、5 一共 25。
注意:数一数加了几个数字,要跟扇区的块数一样。
total pupils = jumlah murid
Add the four sectors: 14 + 10 = 24, 24 + 8 = 32 and 32 + 6 = 38, so 38 pupils in all. 32 leaves out banana's 6, and 28 leaves out rambutan's 10.
Example: sectors of 10, 10 and 5 make 25 altogether.
Watch out: count how many numbers you added; it must equal the number of sectors.
Kelas manakah yang mengumpul tin paling banyak?
收集最多 = mengumpul paling banyak
三个班的铝罐:3 Amanah 25 个、3 Bestari 15 个、3 Cerdik 20 个。最大的数是 25,3 Amanah 的扇区也最大,所以 3 Amanah 收集最多。3 Bestari 15 是最少的;3 Cerdik 20 排第二。
例子:如果 3 Cerdik 多收 10 个变成 30,它就会变成最多。
注意:这个饼分图的数字是铝罐的个数,不是人数。
collecting the most = mengumpul paling banyak
The cans are 3 Amanah 25, 3 Bestari 15 and 3 Cerdik 20. The biggest number is 25, and the 3 Amanah sector is also the biggest, so 3 Amanah collected the most. 3 Bestari with 15 collected the fewest, and 3 Cerdik with 20 is second.
Example: if 3 Cerdik collected 10 more to reach 30, it would become the top class.
Watch out: in this chart the numbers are cans, not pupils.
Berapakah lebih tin yang dikumpul oleh 3 Amanah daripada 3 Bestari?
多收几个 = berapa lebih
3 Amanah 25 个,3 Bestari 15 个,25 − 15 = 10,多 10 个。选 40 是两个数相加;选 5 是拿 3 Amanah 跟 3 Cerdik 比(25 − 20)。
例子:3 Cerdik 比 3 Bestari 多 20 − 15 = 5 个。
注意:先看清楚题目比的是哪两个班。
how many more cans = berapa lebih
3 Amanah has 25 and 3 Bestari has 15, and 25 − 15 = 10, so 10 more. 40 adds the two numbers, and 5 compares 3 Amanah with 3 Cerdik (25 − 20) instead.
Example: 3 Cerdik collected 20 − 15 = 5 more than 3 Bestari.
Watch out: check which two classes the question compares.
Berapakah jumlah tin yang dikumpul oleh ketiga-tiga kelas?
三个班一共 = jumlah tiga kelas
25 + 15 = 40,40 + 20 = 60,三个班一共收集 60 个铝罐。选 40 是漏了 3 Cerdik;选 45 是漏了 3 Bestari。
例子:如果每班各收 20 个,一共 60 个,三个扇区会一样大。
注意:ketiga-tiga 表示三个都要加。
all three classes together = jumlah tiga kelas
25 + 15 = 40 and 40 + 20 = 60, so the three classes collected 60 cans. 40 leaves out 3 Cerdik, and 45 leaves out 3 Bestari.
Example: if each class collected 20, the total would also be 60 and the three sectors would be equal.
Watch out: ketiga-tiga means all three must be added.
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