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分子相差多少 = beza pengangka 分母都是 7，所以缺的分数分母也是 7。用总和的分子减去已知的分子，就是缺的分子。做完把答案放回算式，加起来要等于总和。 例子：1/9 + □ = 5/9 → 5 − 1 = 4 → 4/9。 注意：7/7 是把两个分数加起来，方向错了。

beza pengangka = difference of the numerators Both denominators are 7, so the missing fraction also has denominator 7. The total numerator minus the known numerator gives the missing numerator. Put your answer back and check that the sum is right. Example: 1/9 + □ = 5/9 → 5 − 1 = 4 → 4/9. Watch out: 7/7 comes from adding the two fractions, which is the wrong direction.

求出后约分 = cari, kemudian permudahkan 先用分子相减找出缺的分数，分母照写。得到的分子和分母如果都是双数，就同时除以 2，一直约到不能再约。 例子：□ + 1/10 = 3/10 → 2/10 = 1/5。 注意：约分时分子和分母都要除，只除分子会把分数变小。

cari, kemudian permudahkan = find, then simplify First subtract the numerators to find the missing fraction, keeping the denominator. If the numerator and denominator are both even, divide both by 2, and keep going until it cannot be simplified. Example: □ + 1/10 = 3/10 → 2/10 = 1/5. Watch out: when simplifying, divide both the top and the bottom; dividing only the top makes the fraction smaller.

三分之一换成九分之几 = tukar pertiga kepada persembilan 3 × 3 = 9，所以 1/3 的分子和分母都乘 3。分母相同以后，再用总和的分子减去它的分子，求出缺的分数。 例子：1/3 + □ = 4/9 → 1/3 = 3/9 → 4 − 3 = 1 → 1/9。 注意：7/9 是没有先换分母就直接减 1 得到的。

tukar pertiga kepada persembilan = change thirds into ninths Since 3 × 3 = 9, multiply the top and bottom of 1/3 by 3. When the denominators match, take its numerator away from the total numerator to find the missing fraction. Example: 1/3 + □ = 4/9 → 1/3 = 3/9 → 4 − 3 = 1 → 1/9. Watch out: 7/9 comes from subtracting 1 without changing the denominator first.

找出一对 = cari pasangan 先把每一对里的五分之几换成十分之几，分子分母都乘 2。然后把分子加起来，看哪一对刚好等于总和。 例子：哪一对等于 1/2？1/2 = 5/10，1/10 + 2/5 = 1/10 + 4/10 = 5/10，就是这一对。 注意：分子加起来是 7 不一定对，分母要先换成一样。

cari pasangan = find the pair In each pair, first change the fifths into tenths by multiplying the top and bottom by 2. Then add the numerators and see which pair makes exactly the total. Example: which pair makes 1/2? 1/2 = 5/10, and 1/10 + 2/5 = 1/10 + 4/10 = 5/10, so that pair works. Watch out: numerators that add up to 7 are not enough; the denominators must match first.

应用题 = soalan cerita 先写算式：原有的部分 + □ = 后来的部分。两个分母是 10 和 5，先把五分之几换成十分之几，再用分子相减，最后约成最简分数。 例子：水桶原有 1/8，加水后有 3/4 → 1/8 + □ = 6/8 → 5/8。 注意：2/5 是没有先换分母，直接用 3 − 1 得到的。

soalan cerita = word problem First write the sentence: the part at the start + □ = the part at the end. The denominators are 10 and 5, so change the fifths into tenths, subtract the numerators, then simplify. Example: a pail is 1/8 full and then 3/4 full → 1/8 + □ = 6/8 → 5/8. Watch out: 2/5 comes from doing 3 − 1 without changing the denominator first.