Sebuah baldi besar berisi 7 ℓ 500 mℓ air. Kak Mira menuang semua air itu ke dalam 3 baldi kecil dengan sama banyak. Berapakah isi padu air dalam setiap baldi kecil?
液体体积除法 = bahagi isi padu cecair;平均分 = sama banyak
这一课学把液体平均分成几份。大桶里有 7 ℓ 500 mℓ 水,Kak Mira 把水平均倒进 3 个小桶,每桶多少,就是 7 ℓ 500 mℓ ÷ 3。先除升,升除不完的部分要换成毫升再除。
例子:1 ℓ 的水平均倒进 2 个杯子,每杯 500 mℓ。
注意:除不完的升不能丢掉,它要变成毫升继续分。
dividing liquid volume = bahagi isi padu cecair; equal shares = sama banyak
In this unit we share a liquid into equal parts. A big bucket holds 7 ℓ 500 mℓ of water, and Kak Mira pours it equally into 3 small buckets; each one gets 7 ℓ 500 mℓ ÷ 3. We divide the litres first, and any litres left over are changed into millilitres and shared too.
Example: 1 ℓ of water shared equally between 2 cups gives 500 mℓ each.
Watch out: leftover litres must not be thrown away; they become millilitres and are divided as well.
dividing one unit = bahagi satu unit
With only millilitres, think of the times table backwards: 900 mℓ ÷ 3 = 300 mℓ, because 300 × 3 = 900. For 5 ℓ ÷ 4, which does not share evenly in litres, change 5 ℓ into 5 000 mℓ first and then work out 5 000 ÷ 4 = 1 250 mℓ, which is 1 ℓ 250 mℓ.
Example: 2 ℓ ÷ 5 → 2 000 mℓ ÷ 5 = 400 mℓ.
Watch out: when changing litres to millilitres, multiply by 1 000, not by 100.
no remainder = tiada baki
In long division, divide the litres on the left first: 8 ÷ 4 = 2 with nothing left over. Then divide the millilitres: 640 ÷ 4 = 160, since 600 ÷ 4 = 150 and 40 ÷ 4 = 10 make 160. The answer is 2 ℓ 160 mℓ.
Example: 6 ℓ 300 mℓ ÷ 3 = 2 ℓ 100 mℓ.
Watch out: write each part of the answer above its own column, litres over litres and millilitres over millilitres.
dividing both columns = bahagi kedua-dua lajur
Litres: 6 ÷ 3 = 2 with no remainder. Millilitres: 930 ÷ 3 = 310. The answer is 2 ℓ 310 mℓ.
Example: 4 ℓ 820 mℓ ÷ 2 = 2 ℓ 410 mℓ.
Watch out: 2 ℓ 930 mℓ divides only the litres, and 6 ℓ 310 mℓ divides only the millilitres.
changing the leftover litre = baki ℓ × 1 000
Divide the litres first: 7 ÷ 3 = 2 remainder 1, so write 2 above the litre column. The leftover litre must not be lost: 1 ℓ = 1 000 mℓ, and adding it to the 500 mℓ already there makes 1 500 mℓ. Then 1 500 ÷ 3 = 500, written above the millilitres. The answer is 2 ℓ 500 mℓ.
Example: 5 ℓ 200 mℓ ÷ 2 → 5 ÷ 2 = 2 r 1 → 1 200 ÷ 2 = 600 → 2 ℓ 600 mℓ.
Watch out: understand where the 1 500 comes from: the remainder 1 is 1 × 1 000 mℓ added to the 500 mℓ.
litres too few to share = ℓ tidak cukup dibahagi
2 ÷ 6 does not go, so the litre part of the answer is 0 and all 2 ℓ become the remainder. Change everything into millilitres: 2 000 + 400 = 2 400 mℓ, then 2 400 ÷ 6 = 400. The answer is 400 mℓ, and 0 ℓ need not be written.
Example: 3 ℓ 500 mℓ ÷ 7 → 3 500 ÷ 7 = 500 mℓ.
Watch out: do not drop the 2 ℓ just because 2 is smaller than 6 and work out only 400 ÷ 6.
Cuba
Cikgu Lee ada 1 ℓ 800 mℓ gam. Dia mengisi gam itu ke dalam 6 botol kecil dengan sama banyak. Berapakah isi padu gam dalam setiap botol?
filling small bottles with glue = isi gam ke botol kecil
Six bottles with the same amount means divide: 1 ℓ 800 mℓ ÷ 6. 1 ÷ 6 does not go, so change it all to 1 800 mℓ; 1 800 ÷ 6 = 300. Each bottle holds 300 mℓ. Check: 300 × 6 = 1 800.
Example: 1 ℓ 200 mℓ shared into 4 bottles → 1 200 ÷ 4 = 300 mℓ.
Watch out: 1 ℓ 300 mℓ copies the 1 ℓ straight across, and six such bottles would hold far too much.
Semak dengan darab
2 ℓ 500 mℓ × 3
Hasil bahagi × pembahagi = isi padu asal
ℓ
mℓ
1
2
500
×
3
7
500
2 ℓ 500 mℓ × 3 = 7 ℓ 500 mℓ ✓ sama dengan isi padu asal
checking with multiplication = semak dengan darab
Multiplying a division answer by the divisor should give back the starting amount. 2 ℓ 500 mℓ × 3: 500 × 3 = 1 500 mℓ, so write 500 and carry 1; 2 × 3 + 1 = 7. We get 7 ℓ 500 mℓ, the same as the water in the big bucket, so the answer is right.
Example: 1 ℓ 250 mℓ × 4 = 5 ℓ, so 5 ℓ ÷ 4 = 1 ℓ 250 mℓ is correct.
Watch out: if the check does not match, go back and see whether the remainder was multiplied by 1 000.