Cabar Minda

化成同样的分母 = jadikan penyebut sama Siti 涂了 6/8。分子分母同时除以 2，得到最简分数 3/4，分母正好是 Kumar 的 4 格。所以 Kumar 涂 3 格，两边涂色部分一样大。 例子：10 格涂 2 格，另一张 5 格 → 2/10 = 1/5 → 涂 1 格。 注意：要先确认两张纸一样大，比较才公平。

make the denominators match = jadikan penyebut sama Siti shaded 6/8. Dividing the top and bottom by 2 gives the simplest form 3/4, whose denominator matches Kumar's 4 parts. So Kumar shades 3 parts and both shaded areas are equal. Example: 2 of 10 parts shaded, other strip has 5 parts → 2/10 = 1/5 → shade 1 part. Watch out: the two papers must be the same size, or the comparison is not fair.

Ravi 要涂几格 = berapa bahagian Ravi lorek 先写出 Mei 涂色的分数，再把它化成分母等于 Ravi 格数的等值分数，新的分子就是要涂的格数。也可以看图：纸的每一直列刚好对着长条的一格。 例子：长条 3 格涂 1 格，纸有 9 小格 → 1/3 = 3/9 → 纸上涂 3 格。 注意：长条的每一格比纸上的小格大，不要照抄 Mei 涂了几格。

how many parts Ravi shades = berapa bahagian Ravi lorek Write Mei's shaded fraction, then change it into an equal fraction whose denominator is the number of parts in Ravi's strip. The new numerator is the number of parts to shade. In the picture, each column of the paper lines up with one part of the strip. Example: 1 of 3 parts shaded, paper of 9 squares → 1/3 = 3/9 → shade 3 squares. Watch out: each part of the strip is bigger than a small square, so do not copy Mei's count.

约分找格数 = permudahkan untuk cari bilangan bahagian 先写出 Aiman 涂色的分数。找一个能同时整除分子和分母的数，一起除，让分母变成 Lina 的格数 5，约分后的分子就是要找的格数。 例子：长条 4 格涂 3 格，纸有 8 小格 → 3/4 = 6/8 → 纸上涂 6 格。 注意：Lina 的一格等于 Aiman 的两小格，涂的格数不会和 Aiman 一样。

simplify to find the parts = permudahkan untuk cari bilangan bahagian Write Aiman's shaded fraction first. Find a number that divides both the numerator and the denominator, and divide both so that the denominator becomes 5, the parts in Lina's strip. The new numerator is what you need. Example: 3 of 4 parts shaded, paper of 8 squares → 3/4 = 6/8 → shade 6 squares. Watch out: one part of Lina's strip equals two of Aiman's squares, so the two counts cannot be the same.