Unit 26

Relaks Minda

Permainan Kumpul Bintang: jawab 8 soalan tambah, tolak, darab dan bahagi. Setiap jawapan betul memberi kamu satu bintang!

游戏 = permainan；复习 = ulang kaji 这是整章的复习游戏：一共 8 题，每答对一题就得到一颗星星。题目包括加法、减法、加减混合、乘法、除法和三道文字题（倍数、反求倍数、“少多少”的两步题）。做题前先看清楚符号，再决定怎样算。例子：看到 × 就用乘法；看到“baki”可能是减法，也可能是除法的余数。注意：答错不会扣分，看提示再试一次。

game = permainan, revision = ulang kaji This is a revision game for the whole chapter: 8 questions, and each correct answer earns a star. The questions cover addition, subtraction, mixed addition and subtraction, multiplication, division and three word problems (times as many, working back from times as many, and a two-step 'less than' problem). Read the sign first, then decide how to calculate. Example: × means multiply; 'baki' can mean what is left after subtracting or the remainder after dividing. Watch out: a wrong answer does not lose points; read the hint and try again.

⭐ Bintang 1 / 8

Soalan bintang

4 256 + 1 879 = ?

进位加法 = tambah dengan mengumpul semula 个位 6+9=15 写 5 进 1；十位 5+7+1=13 写 3 进 1；百位 2+8+1=11 写 1 进 1；千位 4+1+1=6。答案 6 135。这一题一共进位三次，每一位都要加上从右边进来的 1。例子：2 345 + 1 678 = 4 023。注意：每一次进位都要加到下一位。

addition with regrouping = tambah dengan mengumpul semula Ones 6+9=15 write 5 carry 1; tens 5+7+1=13 write 3 carry 1; hundreds 2+8+1=11 write 1 carry 1; thousands 4+1+1=6. The answer is 6 135. Example: 2 345 + 1 678 = 4 023. Watch out: add every carried 1 to the next place.

⭐ Bintang 2 / 8

Soalan bintang

9 000 − 3 648 = ?

从零退位 = tolak dari sifar 9 000 = 8 999 + 1。8 999 − 3 648 = 5 351（不用借），再加 1 = 5 352。例子：4 000 − 1 250 = 2 750。注意：检查 5 352 + 3 648 = 9 000。

subtracting from zeros = tolak dari sifar 9 000 = 8 999 + 1. 8 999 − 3 648 = 5 351 (no borrowing), plus 1 = 5 352. Example: 4 000 − 1 250 = 2 750. Watch out: check 5 352 + 3 648 = 9 000.

⭐ Bintang 3 / 8

Soalan bintang

5 240 + 386 − 57 = ?

加减混合 = tambah dan tolak 从左到右：5 240 + 386 = 5 626；5 626 − 57 = 5 569（个位 6 不够减 7，要退位）。5 626 只是第一步，还要再减 57。例子：500 + 120 − 20 = 600。注意：看清楚第一个符号是加，第二个符号是减。

mixed addition and subtraction = tambah dan tolak Left to right: 5 240 + 386 = 5 626; 5 626 − 57 = 5 569 (the ones need regrouping). 5 626 is only step 1. Example: 500 + 120 − 20 = 600. Watch out: the first sign is + and the second is −; read them carefully.

⭐ Bintang 4 / 8

Soalan bintang

4 × 729 = ?

进位乘法 = darab dengan mengumpul semula 个位 4×9=36 写 6 进 3；十位 4×2=8，+3 = 11 写 1 进 1；百位 4×7=28，+1 = 29。答案 2 916。进位的数字要在乘完以后才加上去，不能先加再乘。用约数检查：4 × 700 = 2 800，答案接近。例子：3 × 612 = 1 836。注意：733 是把 4 加上去，不是乘。

multiplication with regrouping = darab dengan mengumpul semula Ones 4×9=36 write 6 carry 3; tens 4×2=8, +3 = 11 write 1 carry 1; hundreds 4×7=28, +1 = 29. The answer is 2 916. Example: 3 × 612 = 1 836. Watch out: 733 adds 4 instead of multiplying.

⭐ Bintang 5 / 8

Soalan bintang

9 360 ÷ 4 = ?

长除法 = bahagi panjang 9 ÷ 4 = 2 余 1；带下 3 成 13，13 ÷ 4 = 3 余 1；带下 6 成 16，16 ÷ 4 = 4；个位 0 ÷ 4 = 0。答案 2 340。检查：4 × 2 340 = 9 360 ✔。例子：6 480 ÷ 3 = 2 160。注意：最后的 0 也要写，234 漏了它。

long division = bahagi panjang 9 ÷ 4 = 2 r 1; bring down 3 to make 13, 13 ÷ 4 = 3 r 1; bring down 6 to make 16, 16 ÷ 4 = 4; ones 0 ÷ 4 = 0. The answer is 2 340. Check: 4 × 2 340 = 9 360 ✔. Example: 6 480 ÷ 3 = 2 160. Watch out: write the final 0 too; 234 leaves it out.

⭐ Bintang 6 / 8

Soalan bintang

Mei Ling ada 1 250 keping pelekat. Kavitha ada 3 kali bilangan pelekat Mei Ling. Berapakah pelekat Kavitha?

几倍 = kali ganda “3 倍” 就是 3 个 1 250：3 × 1 250。十位 3×5=15 写 5 进 1；百位 3×2=6，+1 = 7；千位 3×1=3 → 3 750。例子：2 × 1 500 = 3 000。注意：1 253 是把 3 加上去，不对。

times as many = kali ganda '3 times' means 3 lots of 1 250: 3 × 1 250. Tens 3×5=15 write 5 carry 1; hundreds 3×2=6, +1 = 7; thousands 3×1=3 → 3 750. Example: 2 × 1 500 = 3 000. Watch out: 1 253 adds 3, which is wrong.

⭐ Bintang 7 / 8

Soalan bintang

Pak Karim menanam 2 480 pokok pisang, iaitu 4 kali ganda pokok pisang yang ditanam oleh Pak Ujang. Berapakah jumlah pokok pisang yang ditanam oleh mereka berdua?

反求倍数（两步）= kali ganda songsang Pak Karim 的 2 480 棵是 Pak Ujang 的 4 倍，所以 Pak Ujang 那一份 = 2 480 ÷ 4 = 620（24 个百 ÷ 4 = 6 个百，8 个十 ÷ 4 = 2 个十）。第二步求两块园一共：2 480 + 620 = 3 100。例子：900 是某数的 3 倍 → 某数 = 900 ÷ 3 = 300。注意：已知“大的是小的几倍”，求小的要用除法；620 只是第一步。

working back from times as many, two steps = kali ganda songsang Pak Karim's 2 480 is 4 times Pak Ujang's, so Pak Ujang has 2 480 ÷ 4 = 620 (24 hundreds ÷ 4 = 6 hundreds, 8 tens ÷ 4 = 2 tens). Step 2 finds both farms together: 2 480 + 620 = 3 100. Example: 900 is 3 times a number → the number is 900 ÷ 3 = 300. Watch out: when the bigger amount is 'times' the smaller, divide to find the smaller; 620 is only step 1.

⭐ Bintang 8 / 8

Soalan bintang

Kedai A menjual 2 375 biji kuih bulan. Kedai B menjual 468 biji kurang daripada Kedai A. Berapakah jumlah kuih bulan yang dijual oleh kedua-dua kedai?

“少多少”的两步题 = masalah dua langkah, kurang daripada 第一步：B 店比 A 店少 468 个，所以 B 店 = 2 375 − 468 = 1 907。第二步：两间店一共 = 2 375 + 1 907 = 4 282。例子：哥哥有 500 颗，弟弟比哥哥少 120 颗 → 弟弟 380 颗，两人一共 880 颗。注意：“kurang daripada”要先用减法；5 218 是把 468 加上去算错了 B 店。

two-step 'less than' problem = masalah dua langkah, kurang daripada Step 1: shop B sold 468 fewer than shop A, so B = 2 375 − 468 = 1 907. Step 2: both shops together = 2 375 + 1 907 = 4 282. Example: brother has 500, the younger one has 120 fewer → 380, together 880. Watch out: 'kurang daripada' means subtract first; 5 218 wrongly adds 468 to get shop B.

Ringkasan

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