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找最大的积 = cari hasil darab terbesar 6 的乘法里，不超过 50 的最大积是 6 × 8 = 48，所以商是 8，余数是 50 − 48 = 2。7 baki 8 的余数比 6 大，还可以再分一组，所以不对。 例子：40 ÷ 6 = 6 baki 4。 注意：6 × 9 = 54 比 50 大，不能用。

find the biggest product = cari hasil darab terbesar In the 6 times table, the biggest product not over 50 is 6 × 8 = 48, so the answer is 8 with remainder 50 − 48 = 2. 7 baki 8 is wrong because 8 is bigger than 6. Example: 40 ÷ 6 = 6 baki 4. Watch out: 6 × 9 = 54 is more than 50.

除以 1 000 = bahagi 1 000 除以 1 000，最后三位 432 是余数，前面的 5 是商：5 baki 432。54 baki 32 是除以 100 的答案，543 baki 2 是除以 10 的答案。 例子：5 432 ÷ 10 = 543 baki 2；5 432 ÷ 100 = 54 baki 32。 注意：数一数除数有几个 0，就留几位做余数。

divide by 1 000 = bahagi 1 000 Dividing by 1 000, the last three digits 432 are the remainder and 5 is the answer: 5 baki 432. 54 baki 32 is the answer for ÷ 100 and 543 baki 2 is for ÷ 10. Example: 5 432 ÷ 10 = 543 baki 2; 5 432 ÷ 100 = 54 baki 32. Watch out: the number of zeros in the divisor tells you how many digits make the remainder.

不可能的余数 = baki yang tidak mungkin 除以 5 的时候，余数只可能是 0、1、2、3、4。如果剩下 5 个，就可以再分一组，所以余数不可能是 5 或更大。 例子：除以 3，余数只能是 0、1、2。 注意：余数 0 表示刚好分完。

impossible remainder = baki yang tidak mungkin When dividing by 5, the remainder can only be 0, 1, 2, 3 or 4. If 5 were left, another group could be made, so 5 or more is impossible. Example: dividing by 3, the remainder can only be 0, 1 or 2. Watch out: a remainder of 0 means it shares exactly.

包装题 = masalah bungkus 1 234 ÷ 4：12 ÷ 4 = 3；带下 3，3 比 4 小，商写 0；带下 4 成 34，34 ÷ 4 = 8 余 2。答案 308 包，剩 2 颗。检查：4 × 308 + 2 = 1 234 ✔。 例子：1 005 ÷ 5 = 201。 注意：商中间的 0 不能漏，38 是漏了 0。

packing problem = masalah bungkus 1 234 ÷ 4: 12 ÷ 4 = 3; bring down 3, which is less than 4, so write 0; bring down 4 to make 34, 34 ÷ 4 = 8 r 2. 308 packets with 2 left. Check: 4 × 308 + 2 = 1 234 ✔. Example: 1 005 ÷ 5 = 201. Watch out: do not leave out the 0 in the middle; 38 misses it.