Unit 1
Tambah
Perpustakaan sekolah ada 3 214 buah buku. Sekolah menerima 1 052 buah buku baharu. Berapakah jumlah buku sekarang?
3 214 + 1 052 = ?

加 = tambah;总数 = jumlah
“加”就是把两个数合起来,求出一共有多少。题目里看到 jumlah(总数)、semua(全部)、menerima lagi(再收到)等字眼,通常就要用加法。本单元的加法都不需要进位。
例子:小贩有 2 140 个气球,又买了 1 305 个 → 2 140 + 1 305 = 3 445。
注意:先把相同数位对齐,再从个位开始加。
add = tambah, total = jumlah
Adding means putting two numbers together to find how many there are altogether. Words like jumlah (total), semua (all) and menerima lagi (receive more) usually tell you to add. In this unit no regrouping is needed.
Example: a seller has 2 140 balloons and buys 1 305 more → 2 140 + 1 305 = 3 445.
Watch out: line up the same places first, then start adding from the ones.
Bentuk lazim
Tambah mengikut nilai tempat
Mula dari tempat sa
3 214 + 1 052 = 4 266
竖式 = bentuk lazim;数位 = nilai tempat
用竖式计算时,个位对个位、十位对十位、百位对百位、千位对千位。从个位开始往左加:4+2=6,1+5=6,2+0=2,3+1=4。每一位的和都不超过 9,所以不必进位。
例子:5 123 + 2 604 = 7 727。
注意:数位没对齐,答案就会完全错。
column method = bentuk lazim, place value = nilai tempat
In the column method, ones go under ones, tens under tens, hundreds under hundreds and thousands under thousands. Add from the ones to the left: 4+2=6, 1+5=6, 2+0=2, 3+1=4. Each sum is 9 or less, so there is no regrouping.
Example: 5 123 + 2 604 = 7 727.
Watch out: if the places are not lined up, the answer will be wrong.
Cara lain
Bilang terus dan garis nombor
4 523 + 5 = ?
4 523
4 524
4 525
4 526
4 527
4 528
4 523 + 5 = 4 528
往上数 = bilang terus;数线 = garis nombor
加一个很小的数时,可以从大的数开始往上数。从 4 523 开始,在数线上跳 5 步:4 524、4 525、4 526、4 527、4 528。跳了几步就是加了几。
例子:6 140 + 3 → 6 141、6 142、6 143 → 6 143。
注意:从 4 523 开始,第一跳才是 4 524,起点本身不算一步。
count on = bilang terus, number line = garis nombor
To add a small number, start from the big number and count on. From 4 523, jump 5 steps on the number line: 4 524, 4 525, 4 526, 4 527, 4 528. The number of jumps is the number you add.
Example: 6 140 + 3 → 6 141, 6 142, 6 143 → 6 143.
Watch out: start at 4 523; the first jump lands on 4 524, and the starting point is not a jump.
Cara lain
Kenali abakus
Manik atas = 5 · manik bawah = 1
ribu
ratus
puluh
sa
ribu 2 · ratus 5 + 2 = 7
puluh 0 · sa 5 + 4 = 9
Nombor: 2 709
算盘 = abakus;上珠 = manik atas;下珠 = manik bawah
课本用的算盘每一档有 1 颗上珠和 4 颗下珠。上珠一颗代表 5,下珠一颗代表 1。只有靠近横梁的珠子才算数。从左到右是千位、百位、十位、个位。这个算盘:千位 2,百位 5+2=7,十位 0,个位 5+4=9,所以是 2 709。
例子:某一档拨上 1 颗上珠和 3 颗下珠,就是 5 + 3 = 8。
注意:离开横梁的珠子不算数,而且上珠是 5,不能当成 1 来数。
abacus = abakus, upper bead = manik atas, lower bead = manik bawah
The textbook abacus has 1 upper bead and 4 lower beads on each rod. The upper bead is worth 5 and each lower bead is worth 1. Only beads pushed against the bar count. From the left the rods are thousands, hundreds, tens and ones. Here: thousands 2, hundreds 5+2=7, tens 0, ones 5+4=9, so the number is 2 709.
Example: 1 upper bead and 3 lower beads on a rod make 5 + 3 = 8.
Watch out: beads away from the bar do not count, and the upper bead is 5, not 1.
Cara lain
Tambah dengan abakus
1 520 + 6 173 = ?
ribu
ratus
puluh
sa
① Naik 1 520
ribu
ratus
puluh
sa
② Tambah 6 ribu
ribu
ratus
puluh
sa
③ Tambah 1 ratus, 7 puluh
ribu
ratus
puluh
sa
④ Tambah 3 sa → 7 693
用算盘加 = tambah dengan abakus
先在算盘上拨出第一个数 1 520,再从千位开始,一档一档把 6 173 加上去:千位加 6(拨下上珠,再拨上 1 颗下珠),百位加 1,十位加 7(上珠 + 2 颗下珠),个位加 3。最后读出算盘上的数:7 693。这一题每一档的珠子都够用,直接拨上就可以。
例子:2 101 + 5 062 → 千位拨上 5,十位拨上 6,个位拨上 2 → 7 163。
注意:用算盘加法是从千位开始拨,但读答案时还是千、百、十、个的次序。
adding on an abacus = tambah dengan abakus
Set the first number 1 520 on the abacus, then add 6 173 rod by rod starting from the thousands: thousands +6 (push up 1 upper and 1 lower bead), hundreds +1, tens +7 (the upper bead and 2 lower beads), ones +3. Read the abacus: 7 693. Here every rod has enough beads, so you just push them to the bar.
Example: 2 101 + 5 062 → thousands +5, tens +6, ones +2 → 7 163.
Watch out: on the abacus you start adding at the thousands, but you still read the answer thousands, hundreds, tens, ones.
Semak jawapan
Anggar untuk menyemak
2 310 + 4 480 ≈ ?
Kira: 2 310 + 4 480 = 6 790
2 310 → 2 300 4 480 → 4 500
Anggar: 2 300 + 4 500 = 6 800
6 790 dekat dengan 6 800 → munasabah ✔
约数 = anggar;合理 = munasabah
算完后,把每个数约到最接近的百,再心算一次,看看答案是不是差不多。2 310 约成 2 300,4 480 约成 4 500,2 300 + 4 500 = 6 800。真实答案 6 790 和 6 800 只差 10,所以合理。
例子:1 840 + 3 120 → 约 1 800 + 3 100 = 4 900,真实答案 4 960 很接近。
注意:约到千太粗了:2 000 + 4 000 = 6 000,和 6 790 差很多,就看不出答案对不对。
estimate = anggar, reasonable = munasabah
After adding, round each number to the nearest hundred and add again in your head to see if the answer is close. 2 310 rounds to 2 300 and 4 480 rounds to 4 500, so the estimate is 2 300 + 4 500 = 6 800. The real answer 6 790 is only 10 away, so it is reasonable.
Example: 1 840 + 3 120 → about 1 800 + 3 100 = 4 900; the real answer 4 960 is close.
Watch out: rounding to thousands is too rough here: 2 000 + 4 000 = 6 000 is far from 6 790, so it cannot tell you if the answer is right.
Cuba kira
5 132 + 46 = ?
| 5 | 1 | 3 | 2 | |
| + | 4 | 6 | ||
| ? | ? | ? | ? |
两位数 = nombor dua digit
46 只有十位和个位,所以 4 要对齐 5 132 的十位(3),6 要对齐个位(2)。个位 2+6=8,十位 3+4=7,百位和千位不变。
例子:2 401 + 35 = 2 436。
注意:不要把 46 写在千位和百位下面。
two-digit number = nombor dua digit
46 has only tens and ones, so the 4 goes under the tens (3) of 5 132 and the 6 goes under the ones (2). Ones 2+6=8, tens 3+4=7, and the hundreds and thousands stay the same.
Example: 2 401 + 35 = 2 436.
Watch out: do not write 46 under the thousands and hundreds.
Cari kesilapan
Mira menulis 2 413 + 305 = 5 463. Apakah jawapan yang betul?
找错 = cari kesilapan
Mira 把 305 往左移了一位,把 3 当成了千。305 是三百零五:3 在百位、0 在十位、5 在个位。重新对齐后:个位 3+5=8,十位 1+0=1,百位 4+3=7,千位 2。
例子:1 204 + 402 = 1 606(4 在百位下面)。
注意:三位数的第一个数字在百位。
find the mistake = cari kesilapan
Mira moved 305 one place to the left and treated the 3 as thousands. 305 is three hundred and five: 3 hundreds, 0 tens, 5 ones. Lined up correctly: ones 3+5=8, tens 1+0=1, hundreds 4+3=7, thousands 2.
Example: 1 204 + 402 = 1 606 (the 4 goes under the hundreds).
Watch out: the first digit of a three-digit number is in the hundreds place.
Nombor yang hilang
6 204 + ? = 6 257
缺少的加数 = nombor yang hilang
比较前后两个数的每一位:千位和百位没变,所以要加的数没有千和百;十位从 0 变 5,要加 5 个十;个位从 4 变 7,要加 3 个一。所以缺少的数是 53。
例子:3 120 + ? = 3 145 → 加了 25。
注意:可以用 6 204 + 53 检查是不是等于 6 257。
missing number = nombor yang hilang
Compare each place: thousands and hundreds do not change, so the missing number has none. Tens go from 0 to 5 (add 5 tens) and ones go from 4 to 7 (add 3 ones). The missing number is 53.
Example: 3 120 + ? = 3 145 → 25 was added.
Watch out: check by working out 6 204 + 53 = 6 257.
Ringkasan
Syabas!
Sa · Puluh · Ratus · Ribu
Susun digit mengikut nilai tempat dan tambah dari tempat sa. Anggar untuk menyemak jawapan.
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